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Q101. - (Topic 3)
Refer to the exhibit.
PC1 pings PC2. What three things will CORE router do with the data that is received from PC1? (Choose three.)
A. The data frames will be forwarded out interface FastEthernet0/1 of CORE router.
B. The data frames will be forwarded out interface FastEthernet1/0 of CORE router.
C. CORE router will replace the destination IP address of the packets with the IP address of PC2.
D. CORE router will replace the MAC address of PC2 in the destination MAC address of the frames.
E. CORE router will put the IP address of the forwarding FastEthernet interface in the place of the source IP address in the packets.
F. CORE router will put the MAC address of the forwarding FastEthernet interface in the place of the source MAC address.
Answer: B,D,F
Explanation:
The router will forward the frames out the interface toward the destination – B is correct. Since the router will has the end station already in it’s MAC table as see by the “show arp” command, it will replace the destination MAC address to that of PC2 – D is correct. The router will then replace the source IP address to 172.16.40.1 – E is correct.
Q102. - (Topic 3)
Which two statements describe characteristics of IPv6 unicast addressing? (Choose two.)
A. Global addresses start with 2000::/3.
B. Link-local addresses start with FE00:/12.
C. Link-local addresses start with FF00::/10.
D. There is only one loopback address and it is ::1.
E. If a global address is assigned to an interface, then that is the only allowable address for the interface.
Answer: A,D
Q103. - (Topic 7)
Which feature allows a device to use a switch port that is configured for half-duplex to access the network?
A. CSMA/CD
B. IGMP
C. port security
D. split horizon
Answer: A
Explanation:
Ethernet began as a local area network technology that provided a half-duplex shared channel for stations connected to coaxial cable segments linked with signal repeaters. In this appendix, we take a detailed look at the half-duplex shared-channel mode of operation, and at the CSMA/CD mechanism that makes it work. In the original half-duplex mode, the CSMA/CD protocol allows a set of stations to compete for access to a shared Ethernet channel in a fair and equitable manner. The protocol’s rules determine the behavior of Ethernet stations, including when they are allowed to transmit a frame onto a shared Ethernet channel, and what to do when a collision occurs. Today, virtually all devices are connected to Ethernet switch ports over full-duplex media, such as twisted-pair cables. On this type of connection, assuming that both devices can support the full-duplex mode of operation and that Auto-Negotiation (AN) is enabled, the AN protocol will automatically select the highest-performance mode of operation supported by the devices at each end of the link. That will result in full-duplex mode for the vast majority of Ethernet connections with modern interfaces that support full duplex and AN.
Q104. - (Topic 3)
Which address are OSPF hello packets addressed to on point-to-point networks?
A. 224.0.0.5
B. 172.16.0.1
C. 192.168.0.5
D. 223.0.0.1
E. 254.255.255.255
Answer: A
Explanation:
Why does the show ip ospf neighbor Command Reveal Neighbors in the Init State? http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080093f11.shtml OSPF hello packets have a destination address of 224.0.0.5 (the all ospf routers multicast
address).
Q105. - (Topic 3)
If an Ethernet port on a router was assigned an IP address of 172.16.112.1/20, what is the maximum number of hosts allowed on this subnet?
A. 1024
B. 2046
C. 4094
D. 4096
E. 8190
Answer: C
Explanation:
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1 Add them up and you get 255. Add one for the all zeros option, and the total is 256. Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255. The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2^20 minus one if you have subnet zero enabled, or minus 2 if not. You asked about the number of hosts. That will be 32 minus the number of network bits, minus two. So calculate it as (2^(32-20))-2, or (2^12)-2 = 4094
Q106. - (Topic 2)
Refer to the exhibit.
What two things can the technician determine by successfully pinging from this computer to the IP address 172.16.236.1? (Choose two)
A. The network card on the computer is functioning correctly.
B. The default static route on the gateway router is correctly configured.
C. The correct default gateway IP address is configured on the computer.
D. The device with the IP address 172.16.236.1 is reachable over the network.
E. The default gateway at 172.16.236.1 is able to forward packets to the internet.
Answer: A,D
Explanation:
The source and destination addresses are on the same network therefore, a default gateway is not necessary for communication between these two addresses.
Q107. CORRECT TEXT - (Topic 6)
This topology contains 3 routers and 1 switch. Complete the topology.
Drag the appropriate device icons to the labeled Device Drag the appropriate connections to the locations labeled Connections. Drag the appropriate IP addresses to the locations labeled IP address
(Hint: use the given host addresses and Main router information) To remove a device or connection, drag it away from the topology.
Use information gathered from the Main router to complete the configuration of any additional routers.
No passwords are required to access the Main router. The config terminal command has been disabled for the HQ router. The router does not require any configuration.
Configure each additional router with the following:
Configure the interfaces with the correct IP address and enable the interfaces.
Set the password to allow console access to consolepw
Set the password to allow telnet access to telnetpw
Set the password to allow privilege mode access to privpw
Not E: Because routes are not being added to the configurations, you will not be able to ping through the internetwork.
All devices have cable autosensing capabilities disabled.
All hosts are PC’s
Answer: Specify appropriate devices and drag them on the "Device" boxes For the device at the bottom-right box, we notice that it has 2 interfaces Fa0/2 and Fa0/4; moreover the link connects the PC on the right with the device on the bottom-right is a straight-through link -> it is a switch The question stated that this topology contains 3 routers and 1 switch -> two other devices are routers Place them on appropriate locations as following: (Host D and host E will be automatically added after placing two routers. Click on them to access neighboring routers) Specify appropriate connections between these devices:
+
The router on the left is connected with the Main router through FastEthernet interfaces: use a crossover cable
+
The router on the right is connected with the Main router through Serial interfaces: use a
serial cable
+
The router on the right and the Switch: use a straight-through cable
+
The router on the left and the computer: use a crossover cable (To remember which type of cable you should use, follow these tips:
-
To connect two serial interfaces of 2 routers we use serial cable
-
To specify when we use crossover cable or straight-through cable, we should remember: Group 1: Router, Host, Server Group 2: Hub, Switch One device in group 1 + One device in group 2: use straight-through cable Two devices in the same group: use crossover cable For example, we use straight-through cable to connect switch to router, switch to host, hub to host, hub to server... and we use crossover cable to connect switch to switch, switch to hub, router to router, host to host.) Assign appropriate IP addresses for interfaces: From Main router, use show running-config command.
(Notice that you may see different IP addresses in the real CCNA exam, the ones shown above are just used for demonstration)
From the output we learned that the ip address of Fa0/0 interface of the Main router is
192.168.152.177/28. This address belongs to a subnetwork which has:
Increment: 16 (/28 = 255.255.255.240 or 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.168.152.176 (because 176 = 16 * 11 and 176 < 177)
Broadcast address: 192.168.152.191 (because 191 = 176 + 16 - 1)
And we can pick up an ip address from the list that belongs to this subnetwork:
192.168.152.190 and assign it to the Fa0/0 interface the router on the left Use the same method for interface Serial0/0 with an ip address of 192.168.152.161 Increment: 16 Network address: 192.168.152.160 (because 160 = 16 * 10 and 160 < 161) Broadcast address: 192.168.152.175 (because 176 = 160 + 16 - 1) -> and we choose 192.168.152.174 for Serial0/0 interface of the router on the right Interface Fa0/1 of the router on the left IP (of the computer on the left) : 192.168.152.129/28 Increment: 16 Network address: 192.168.152.128 (because 128 = 16 * 8 and 128 < 129) Broadcast address: 192.168.152.143 (because 143 = 128 + 16 - 1) -> we choose 192.168.152.142 from the list Interface Fa0/0 of the router on the right IP (of the computer on the left) : 192.168.152.225/28 Increment: 16 Network address: 192.168.152.224 (because 224 = 16 * 14 and 224 < 225) Broadcast address: 192.168.152.239 (because 239 = 224 + 16 - 1) -> we choose 192.168.152.238 from the list Let's have a look at the picture below to summarize Configure two routers on the left and right with these commands: Router1 = router on the left Assign appropriate IP addresses to Fa0/0 & Fa0/1 interfaces: Router1>enable Router1#configure terminal Router1(config)#interface fa0/0 Router1(config-if)#ip address 192.168.152.190 255.255.255.240 Router1(config-if)#no shutdown Router1(config-if)#interface fa0/1 Router1(config-if)#ip address 192.168.152.142 255.255.255.240 Router1(config-if)#no shutdown Set passwords (configure on two routers)
+
Console password: Router1(config-if)#exit Router1(config)#line console 0
Router1(config-line)#password consolepw Router1(config-line)#login Router1(config-line)#exit
+
Telnet password: Router1(config)#line vty 0 4 Router1(config-line)#password telnetpw Router1(config-line)#login Router1(config-line)#exit
+
Privilege mode password: Router1(config)#enable password privpw Save the configuration: Router1(config)#exit Router1#copy running-config startup-config Configure IP addresses of Router2 (router on the right) Router2>enable Router2#configure terminal Router2(config)#interface fa0/0 Router2(config-if)#ip address 192.168.152.238 255.255.255.240 Router2(config-if)#no shutdown Router2(config-if)#interface serial0/0 Router2(config-if)#ip address 192.168.152.174 255.255.255.240 Router2(config-if)#no shutdown Then set the console, telnet and privilege mode passwords for Router2 as we did for Router1, remember to save the configuration when you finished.
Q108. - (Topic 5)
Refer to the exhibit.
An administrator replaced the 10/100 Mb NIC in a desktop PC with a 1 Gb NIC and now the PC will not connect to the network. The administrator began troubleshooting on the switch. Using the switch output shown, what is the cause of the problem?
A. Speed is set to 100Mb/s.
B. Input flow control is off.
C. Encapsulation is set to ARPA.
D. The port is administratively down.
E. The counters have never been cleared.
Answer: A
Explanation:
For PC to switch connectivity, the speed settings must match. In this case, the 1 Gb NIC will not be able to communicate with a 100Mb fast Ethernet interface, unless the 1Gb NIC can be configured to connect at 100Mb.
Q109. - (Topic 1)
How does TCP differ from UDP? (Choose two.)
A. TCP provides best effort delivery.
B. TCP provides synchronized communication.
C. TCP segments are essentially datagrams.
D. TCP provides sequence numbering of packets.
E. TCP uses broadcast delivery.
Answer: B,D
Explanation:
Because TCP is a connection-oriented protocol responsible for ensuring the transfer of a datagram from the source to destination machine (end-to-end communications), TCP must receive communications messages from the destination machine to acknowledge receipt of the datagram. The term virtual circuit is usually used to refer to the handshaking that goes on between the two end machines, most of which are simple acknowledgment messages (either confirmation of receipt or a failure code) and datagram sequence numbers. Rather than impose a state within the network to support the connection, TCP uses synchronized state between the two endpoints. This synchronized state is set up as part of an initial connection process, so TCP can be regarded as a connection-oriented protocol. Much of the protocol design is intended to ensure that each local state transition is communicated to, and acknowledged by, the remote party.
Reference: http://en.wikibooks.org/wiki/Communication_Networks/TCP_and_UDP_Protocols
Q110. - (Topic 3)
What information can be used by a router running a link-state protocol to build and maintain its topological database? (Choose two.)
A. hello packets
B. SAP messages sent by other routers
C. LSAs from other routers
D. beacons received on point-to-point links
E. routing tables received from other link-state routers
F. TTL packets from designated routers
Answer: A,C
Explanation:
Reference 1: http://www.ciscopress.com/articles/article.asp?p=24090&seqNum=4
Link state protocols, sometimes called shortest path first or distributed database protocols, are built around a well-known algorithm from graph theory, E. W. Dijkstra'a shortest path algorithm. Examples of link state routing protocols are: Open Shortest Path First (OSPF) for IP The ISO's Intermediate System to Intermediate System (IS-IS) for CLNS and IP DEC's DNA Phase V Novell's NetWare Link Services Protocol (NLSP) Although link state protocols are rightly considered more complex than distance vector protocols, the basic functionality is not complex at all:
1.
Each router establishes a relationship—an adjacency—with each of its neighbors.
2.
Each router sends link state advertisements (LSAs), some
3.
Each router stores a copy of all the LSAs it has seen in a database. If all works well, the databases in all routers should be identical.
4.
The completed topological database, also called the link state database, describes a graph of the internetwork. Using the Dijkstra algorithm, each router calculates the shortest path to each network and enters this information into the route table. OSPF Tutorial
