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Q141. - (Topic 2)
What is true of using group functions on columns that contain NULL values?
A. Group functions on columns ignore NULL values.
B. Group functions on columns returning dates include NULL values.
C. Group functions on columns returning numbers include NULL values.
D. Group functions on columns cannot be accurately used on columns that contain NULL values.
E. Group functions on columns include NULL values in calculations if you use the keyword INC_NULLS.
Answer: A
Explanation: group functions on column ignore NULL values
Incorrect Answer: Bgroup functions on column ignore NULL values Cgroup functions on column ignore NULL values DNVL function can be use for column with NULL values Eno such INC_NULLS keyword
Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 5-12
Q142. - (Topic 2)
Which substitution variable would you use if you want to reuse the variable without prompting the user each time?
A. &
B. ACCEPT
C. PROMPT
D. &&
Answer: D
Explanation:
To reuse the variable without prompting the user each time you can use && substitution
variable.
Incorrect Answers
A:This substitution variable will prompt the user each time.
B:ACCEPT is command, not substitution variable. It used to define more accurate or
specific prompt or when you want more output to display as the values are defined.
C:PROMPT is part of the ACCEPT command, it is not a variable.
OCP Introduction to Oracle 9i: SQL Exam Guide, Jason Couchman, p. 165-173
Chapter 4: Sub queries
Q143. - (Topic 2)
You need to modify the STUDENTS table to add a primary key on the STUDENT_ID column. The table is currently empty.
Which statement accomplishes this task?
A. ALTER TABLE students ADD PRIMARY KEY student_id;
B. ALTER TABLE students ADD CONSTRAINT PRIMARY KEY (student_id);
C. ALTER TABLE students ADD CONSTRAINT stud_id_pk PRIMARY KEY student_id;
D. ALTER TABLE students ADD CONSTRAINT stud_id_pk PRIMARY KEY (student_id); E. ALTER TABLE students MODIFY CONSTRAINT stud_id_pk PRIMARY KEY (student_id);
Answer: D
Explanation:
ALTER TABLE table_name
ADD [CONSTRAINT constraint] type (coloumn);
Incorrect Answer:
Awrong syntax
Bwrong syntax
Cwrong syntax
Eno such MODIFY keyword
Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 10-17
Q144. - (Topic 2)
View the Exhibit and examine the structure and data in the INVOICE table.
Which statements are true regarding data type conversion in expressions used in queries? (Choose all that apply.)
A. inv_amt ='0255982' : requires explicit conversion
B. inv_date > '01-02-2008' : uses implicit conversion
C. CONCAT(inv_amt,inv_date) : requires explicit conversion
D. inv_date = '15-february-2008' : uses implicit conversion
E. inv_no BETWEEN '101' AND '110' : uses implicit conversion
Answer: D,E
Explanation:
In some cases, the Oracle server receives data of one data type where it expects data of a different data type. When this happens, the Oracle server can automatically convert the data to the expected data type. This data type conversion can be done implicitly by the Oracle server or explicitly by the user. Explicit data type conversions are performed by using the conversion functions. Conversion functions convert a value from one data type to another. Generally, the form of the function names follows the convention data type TO data type. The first data type is the input data type and the second data type is the output. Note: Although implicit data type conversion is available, it is recommended that you do the explicit data type conversion to ensure the reliability of your SQL statements.
Q145. - (Topic 2)
Which two statements complete a transaction? (Choose two)
A. DELETE employees;
B. DESCRIBE employees;
C. ROLLBACK TO SAVEPOINT C;
D. GRANT SELECT ON employees TO SCOTT;
E. ALTER TABLE employeesSET UNUSED COLUMN sal;
F. Select MAX(sal)FROM employeesWHERE department_id = 20;
Answer: D,E
Explanation:
D: GRANT is a DML operation which will cause an implicit commit
E: It is important to understand that an implicit COMMIT occurs on the database when a user exits SQL*Plus or issues a data-definition language (DDL) command such as a CREATE TABLE statement, used to create a database object, or an ALTER TABLE statement, used to alter a database object.
Incorrect Answers A:The DELETE command is data-manipulation language (DML) command and it does not complete a transaction. B:The DESCRIBE command is internal SQL*Plus command and it has nothing to do with completion a transaction.
C: ROLLBACK is not used to commit or complete a transaction, it is used to undo a transaction F:SELECT command is used to retrieve data. It does not complete a transaction.
OCP Introduction to Oracle 9i: SQL Exam Guide, Jason Couchman, p. 281-282 Chapter 3: Advanced Data Selection in Oracle
Q146. - (Topic 1)
Examine these statements:
CREATE ROLE registrar;
GRANT UPDATE ON student_grades TO registrar;
GRANT registrar to user1, user2, user3;
What does this set of SQL statements do?
A. The set of statements contains an error and does not work.
B. It creates a role called REGISTRAR, adds the MODIFY privilege on the STUDENT_GRADES object to the role, and gives the REGISTRAR role to three users.
C. It creates a role called REGISTRAR, adds the UPDATE privilege on the STUDENT_GRADES object to the role, and gives the REGISTRAR role to three users.
D. It creates a role called REGISTRAR, adds the UPDATE privilege on the STUDENT_GRADES object to the role, and creates three users with the role.
E. It creates a role called REGISTRAR, adds the UPDATE privilege on three users, and gives the REGISTRAR role to the STUDENT_GRADES object.
F. It creates a role called STUDENT_GRADES, adds the UPDATE privilege on three users, and gives the UPDATE role to the registrar.
Answer: C
Explanation: the statement will create a role call REGISTRAR, grant UPDATE on student_grades to registrar, grant the role to user1,user2 and user3.
Incorrect Answer: Athe statement does not contain error Bthere is no MODIFY privilege Dstatement does not create 3 users with the role Eprivilege is grant to role then grant to user Fprivilege is grant to role then grant to user
Q147. - (Topic 1)
Which three statements are true regarding the data types in Oracle Database 10g/11g? (Choose three.)
A. The BLOB data type column is used to store binary data in an operating system file
B. The minimum column width that can be specified for a VARCHAR2 data type column is one
C. A TIMESTAMP data type column stores only time values with fractional seconds
D. The value for a CHAR data type column is blank-padded to the maximum defined column width
E. Only One LONG column can be used per table
Answer: B,D,E
Explanation:
LONG Character data in the database character set, up to 2GB. All the functionality of LONG (and more) is provided by CLOB; LONGs should not be used in a modern database, and if your database has any columns of this type they should be converted to CLOB. There can only be one LONG column in a table. DVARCHAR2 Variable-length character data, from 1 byte to 4KB. The data is stored in the database character set. The VARCHAR2 data type must be qualified with a number indicating the maximum length of the column. If a value is inserted into the column that is less than this, it is not a problem: the value will only take up as much space as it needs. If the value is longer than this maximum, the INSERT will fail with an error. VARCHAR2(size) Variable-length character data (A maximum size must be specified: minimum size is 1; maximum size is 4,000.) BLOB Like CLOB, but binary data that will not undergo character set conversion by Oracle
Net.
BFILE A locator pointing to a file stored on the operating system of the database server.
The size of the files is limited to 4GB.
TIMESTAMP This is length zero if the column is empty, or up to 11 bytes, depending on
the precision specified.
Similar to DATE, but with precision of up to 9 decimal places for the seconds, 6 places by
default.
Q148. - (Topic 2)
View the Exhibit and examine the structures of the EMPLOYEES and DEPARTMENTS tables.
You want to update the EMPLOYEES table as follows:4 ? 4;
-Update only those employees who work in Boston or Seattle (locations 2900 and 2700).
-Set department_id for these employees to the department_id corresponding to London
(location_id 2100).
-Set the employees' salary in location_id 2100 to 1.1 times the average salary of their department.
-Set the employees' commission in location_id 2100 to 1.5 times the average commission of their department.
You issue the following command: SQL>UPDATE employees SET department_id = (SELECT department_id FROM departments WHERE location_id = 2100), (salary, commission) = (SELECT 1.1*AVG(salary), 1.5*AVG(commission) FROM employees, departments WHERE departments.location_id IN(2900,2700,2100)) WHERE department_id IN (SELECT department_id FROM departments WHERE location_id = 2900 OR location_id = 2700)
What is the outcome?
A. It executes successfully and gives the correct result.
B. It executes successfully but does not give the correct result.
C. It generates an error because a subquery cannot have a join condition in an UPDATE statement.
D. It generates an error because multiple columns (SALARY, COMMISION) cannot be specified together in an UPDATE statement.
Answer: B
Q149. - (Topic 2)
Examine the structure of the EMP_DEPT_VU view:
Which SQL statement produces an error?
A. SELECT *
FROM emp_dept_vu;
B. SELECT department_id, SUM(salary)
FROM emp_dept_vu
GROUP BY department_id;
C. SELECT department_id, job_id, AVG(salary)
FROM emp_dept_vu
GROUP BY department_id, job_id;
D. SELECT job_id, SUM(salary)
FROM emp_dept_vu
WHERE department_id IN (10,20)
GROUP BY job_id
HAVING SUM(salary) > 20000;
E. None of the statements produce an error; all are valid.
Answer: E
Explanation: Explanation: None of the statements produce an error. Incorrect Answer: AStatement will not cause error BStatement will not cause error CStatement will not cause error DStatement will not cause error
Q150. - (Topic 2)
View the Exhibits and examine the structures of the CUSTOMERS, SALES, and COUNTRIES tables.
You need to generate a report that shows all country names, with corresponding customers (if any) and sales details (if any), for all customers.
Which FROM clause gives the required result?
A. FROM sales JOIN customers USING (cust_id) FULL OUTER JOIN countries USING (country_id);
B. FROM sales JOIN customers USING (cust_id) RIGHT OUTER JOIN countries USING (country_id);
C. FROM customers LEFT OUTER JOIN sales USING (cust_id) RIGHT OUTER JOIN countries USING (country_id);
D. FROM customers LEFT OUTER JOIN sales USING (cust_id) LEFT OUTER JOIN countries USING (country_id);
Answer: C
