we provide High quality Oracle java se 8 programmer i 1z0 808 pdf braindumps which are the best for clearing exam 1z0 808 test, and to get certified by Oracle Java SE 8 Programmer I. The exam 1z0 808 Questions & Answers covers all the knowledge points of the real 1z0 808 pdf exam. Crack your Oracle exam 1z0 808 Exam with latest dumps, guaranteed!
♥♥ 2021 NEW RECOMMEND ♥♥
Free VCE & PDF File for Oracle 1z0-808 Real Exam (Full Version!)
★ Pass on Your First TRY ★ 100% Money Back Guarantee ★ Realistic Practice Exam Questions
Free Instant Download NEW 1z0-808 Exam Dumps (PDF & VCE):
Available on:
http://www.surepassexam.com/1z0-808-exam-dumps.html
Q1. Given:
Which two code fragments are valid?
A. Option A
B. Option B
C. Option C
D. Option D
E. Option E
Answer: B,C
Explanation: When an abstract class is subclassed, the subclass usually provides implementations for all of the abstract methods in its parent class (C). However, if it does not, then the subclass must also be declared abstract (B). Note: An abstract class is a class that is declared abstract—it may or may not include abstract methods. Abstract classes cannot be instantiated, but they can be subclassed.
Q2. Given:
public class Test {
public static void main(String[] args) {
int day = 1;
switch (day) {
case "7": System.out.print("Uranus");
case "6": System.out.print("Saturn");
case "1": System.out.print("Mercury");
case "2": System.out.print("Venus");
case "3": System.out.print("Earth");
case "4": System.out.print("Mars");
case "5": System.out.print("Jupiter");
}
}
}
Which two modifications, made independently, enable the code to compile and run?
A. Adding a break statement after each print statement
B. Adding a default section within the switch code-block
C. Changing the string literals in each case label to integer
D. Changing the type of the variable day to String
E. Arranging the case labels in ascending order
Answer: A,C
Explanation: The following will work fine:
public class Test {
public static void main(String[] args) {
int day = 1;
switch (day) {
case 7: System.out.print("Uranus"); break;
case 6: System.out.print("Saturn"); break;
case 1: System.out.print("Mercury"); break;
case 2: System.out.print("Venus"); break;
case 3: System.out.print("Earth"); break;
case 4: System.out.print("Mars"); break;
case 5: System.out.print("Jupiter"); break;
}
}
}
Q3. Given:
What is the result?
A. Initialized Started
B. Initialized Started Initialized
C. Compilation fails
D. An exception is thrown at runtime
Answer: B
Q4. Given the definitions of the MyString class and the Test class:
What is the result?
A. Option A
B. Option B
C. Option C
D. Option D
Answer: C
Q5. Given:
What is the result?
A. myStr: 9009, myNum: 9009
B. myStr: 7007, myNum: 7007
C. myStr: 7007, myNum: 9009
D. Compilation fails
Answer: C
Q6. You are asked to develop a program for a shopping application, and you are given the following information:
. The application must contain the classes Toy, EduToy, and consToy. The Toy class is the superclass of the other two classes.
. The int caicuiatePrice (Toy t) method calculates the price of a toy.
. The void printToy (Toy t) method prints the details of a toy.
Which definition of the Toy class adds a valid layer of abstraction to the class hierarchy?
A. Option A
B. Option B
C. Option C
D. Option D
Answer: A
Q7. Given:
Class A { }
Class B { }
Interface X { }
Interface Y { }
Which two definitions of class C are valid?
A. Class C extends A implements X { }
B. Class C implements Y extends B { }
C. Class C extends A, B { }
D. Class C implements X, Y extends B { }
E. Class C extends B implements X, Y { }
Answer: A,E
Explanation: extends is for extending a class.
implements is for implementing an interface. Java allows for a class to implement many interfaces.
Q8. Given:
A. ns = 50 S = 125 ns = 125 S = 125 ns = 100 S = 125
B. ns = 50 S = 125 ns = 125 S = 125 ns = 0 S = 125
C. ns = 50 S = 50 ns = 125 S = 125 ns = 100 S = 100
D. ns = 50 S = 50 ns = 125 S = 125 ns = 0 S = 125
Answer: B
Q9. Given the code fragment:
List colors = new ArrayList();
colors.add("green");
colors.add("red");
colors.add("blue");
colors.add("yellow");
colors.remove(2);
colors.add(3,"cyan");
System.out.print(colors);
What is the result?
A. [green, red, yellow, cyan]
B. [green, blue, yellow, cyan]
C. [green, red, cyan, yellow]
D. Am IndexOutOfBoundsException is thrown at runtime
Answer: A
Explanation: First the list [green, red, blue, yellow] is build.
The blue element is removed:
[green, red, yellow]
Finally the element cyan is added at then end of the list (index 3).
[green, red, yellow, cyan]
Q10. Given the code fragment:
What is the result?
A. 100
B. 101
C. 102
D. 103
E. Compilation fails
Answer: E
