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Q151. - (Topic 1)
You need to display the first names of all customers from the CUSTOMERS table that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?
A.
SELECT cust_first_name FROM customers WHERE INSTR(cust_first_name, 'e')<>0 AND SUBSTR(cust_first_name, -2, 1)='a'
B.
SELECT cust_first_name FROM customers WHERE INSTR(cust_first_name, 'e')<>'' AND SUBSTR(cust_first_name, -2, 1)='a'
C.
SELECT cust_first_name FROM customers WHERE INSTR(cust_first_name, 'e')IS NOT NULL AND SUBSTR(cust_first_name, 1,-2)='a'
D.
SELECT cust_first_name FROM customers WHERE INSTR(cust_first_name, 'e')<>0 AND SUBSTR(cust_first_name, LENGTH(cust_first_name),-2)='a'
Answer: A
Explanation:
The SUBSTR(string, start position, number of characters) function accepts three
parameters and returns a string consisting of the number of characters extracted from the
source string, beginning at the specified start position:
substr('http://www.domain.com',12,6) = domain
The position at which the first character of the returned string begins.
When position is 0 (zero), then it is treated as 1.
When position is positive, then the function counts from the beginning of string to find the
first character.
When position is negative, then the function counts backward from the end of string.
substring_length
The length of the returned string. SUBSTR calculates lengths using characters as defined
by the input character set. SUBSTRB uses bytes instead of characters. SUBSTRC uses
Unicode complete characters.
SUBSTR2 uses UCS2 code points. SUBSTR4 uses UCS4 code points.
When you do not specify a value for this argument, then the function
The INSTR(source string, search item, [start position],[nth occurrence of search item])
function returns a number that represents the position in the source string, beginning from
the given start position, where the nth occurrence of the search item begins:
instr('http://www.domain.com','.',1,2) = 18
Q152. - (Topic 1)
View the Exhibit and examine the structure of the PROMOTIONS table.
Using the PROMOTIONS table, you need to find out the names and cost of all the promos done on 'TV' and 'internet' that ended in the time interval 15th March '00 to 15th October '00.
Which two queries would give the required result? (Choose two.)
A. SELECT promo_name, promo_cost FROM promotions WHERE promo_category IN ('TV', 'internet') AND promo_end_date BETWEEN '15-MAR-00' AND '15-OCT-00'
B. SELECT promo_name, promo_cost FROM promotions WHERE promo_category = 'TV' OR promo_category ='internet' AND promo_end_date >='15-MAR-00' OR promo_end_date <='15-OCT-00'
C. SELECT promo_name, promo_cost FROM promotions WHERE (promo_category BETWEEN 'TV' AND 'internet') AND (promo_end_date IN ('15-MAR-00','15-OCT-00'));
D. SELECT promo_name, promo_cost FROM promotions WHERE (promo_category = 'TV' OR promo_category ='internet') AND (promo_end_date >='15-MAR-00' AND promo_end_date <='15-OCT-00');
Answer: A,D
Q153. - (Topic 1)
User Mary has a view called EMP_DEPT_LOC_VU that was created based on the EMPLOYEES, DEPARTMENTS, and LOCATIONS tables. She has the privilege to create a public synonym, and would like to create a synonym for this view that can be used by all users of the database.
Which SQL statement can Mary use to accomplish that task?
A. CREATE PUBLIC SYNONYM EDL_VU ON emp_dept_loc_vu;
B. CREATE PUBLIC SYNONYM EDL:VU FOR mary (emp_dept_loc_vu);
C. CREATE PUBLIC SYNONYM EDL_VU FOR emp_dept_loc_vu;
D. CREATE SYNONYM EDL_VU ON emp_dept_loc_vu FOR EACH USER;
E. CREATE SYNONYM EDL_VU FOR EACH USER ON emp_dept_loc_vu;
F. CREATE PUBLIC SYNONYM EDL_VU ON emp_dept_loc_vu FOR ALL USERS;
Answer: C
Explanation:
The general syntax to create a synonym is:
CREATE [PUBLIC] SYNONYM synonym FOR object;
Q154. - (Topic 2)
View the Exhibit and examine the structure of the EMPLOYEES table.
Examine the data in the ENAME and HIREDATE columns of the EMPLOYEES table:
ENAME HIREDATE
SMITH 17-DEC-80 ALLEN 20-FEB-81 WARD 22-FEB-81
You want to generate a list of user IDs as follows: USERID
Smi17DEC80 All20FEB81 War22FEB81
You issue the following query:
SQL>SELECT CONCAT(SUBSTR(INITCAP(ename),1,3), REPLACE(hiredate,'-'))
"USERID"
FROM employees;
What is the outcome?
A. It executes successfully and gives the correct output.
B. It executes successfully but does not give the correct output.
C. It generates an error because the REPLACE function is not valid.
D. It generates an error because the SUBSTR function cannot be nested in the CONCAT function.
Answer: A
Explanation:
REPLACE(text, search_string,replacement_string) Searches a text expression for a character string and, if found, replaces it with a specified replacement string The REPLACE Function The REPLACE function replaces all occurrences of a search item in a source string with a replacement term and returns the modified source string. If the length of the replacement term is different from that of the search item, then the lengths of the returned and source strings will be different. If the search string is not found, the source string is returned unchanged. Numeric and date literals and expressions are evaluated before being implicitly cast as characters when they occur as parameters to the REPLACE function. The REPLACE function takes three parameters, with the first two being mandatory. Its syntax is REPLACE (source string, search item, [replacement term]). If the replacement term parameter is omitted, each occurrence of the search item is removed from the source string. In other words, the search item is replaced by an empty string. . The following queries illustrate the REPLACE function with numeric and date expressions: Query 1: select replace(10000-3,'9','85') from dual Query 2: select replace(sysdate, 'DEC','NOV') from dual
Q155. - (Topic 2)
View the Exhibit and examine the structure of the PROMOTIONS table.
Evaluate the following SQL statement:
SQL>SELECT promo_name,CASE
WHEN promo_cost >=(SELECT AVG(promo_cost)
FROM promotions
WHERE promo_category='TV')
then 'HIGH'
else 'LOW'
END COST_REMARK
FROM promotions;
Which statement is true regarding the outcome of the above query?
A. It shows COST_REMARK for all the promos in the table.
B. It produces an error because the subquery gives an error.
C. It shows COST_REMARK for all the promos in the promo category 'TV'.
D. It produces an error because subqueries cannot be used with the CASE expression.
Answer: A
Q156. - (Topic 1)
Which is an iSQL*Plus command?
A. INSERT
B. UPDATE
C. SELECT
D. DESCRIBE
E. DELETE
F. RENAME
Answer: D
Explanation: Explanation:
The only SQL*Plus command in this list: DESCRIBE. It cannot be used as SQL command.
This command returns a description of tablename, including all columns in that table, the
datatype for each column and an indication of whether the column permits storage of NULL
values.
Incorrect Answer:
A INSERT is not a SQL*PLUS command
B UPDATE is not a SQL*PLUS command
C SELECT is not a SQL*PLUS command
E DELETE is not a SQL*PLUS command
F RENAME is not a SQL*PLUS command
Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 7
Q157. - (Topic 1)
See the structure of the PROGRAMS table:
Which two SQL statements would execute successfully? (Choose two.)
A. SELECT NVL(ADD_MONTHS(END_DATE,1),SYSDATE) FROM programs;
B. SELECT TO_DATE(NVL(SYSDATE-END_DATE,SYSDATE)) FROM programs;
C. SELECT NVL(MONTHS_BETWEEN(start_date,end_date),'Ongoing') FROM programs;
D. SELECT NVL(TO_CHAR(MONTHS_BETWEEN(start_date,end_date)),'Ongoing') FROM programs;
Answer: A,D
Explanation:
NVL Function
Converts a null value to an actual value:
Data types that can be used are date, character, and number.
Data types must match:
–
NVL(commission_pct,0)
–
NVL(hire_date,'01-JAN-97')
–
NVL(job_id,'No Job Yet')
MONTHS_BETWEEN(date1, date2): Finds the number of months between date1 and date2 The result can be positive or negative. If date1 is later than date2, the result is positive; if date1 is earlier than date2, the result is negative. The noninteger part of the result represents a portion of the month. MONTHS_BETWEEN returns a numeric value. - answer C NVL has different datatypes -numeric and strings, which is not possible!
The data types of the original and if null parameters must always be compatible. They must either be of the same type, or it must be possible to implicitly convert if null to the type of the original parameter. The NVL function returns a value with the same data type as the original parameter.
Q158. - (Topic 1)
You need to calculate the number of days from 1st January 2007 till date . Dates are stored in the default format of dd-mon-rr. Which two SQL statements would give the required output? (Choose two.)
A. SELECT SYSDATE - '01-JAN-2007' FROM DUAL:
B. SELECT SYSDATE - TOJDATE(X)1/JANUARY/2007") FROM DUAL:
C. SELECT SYSDATE - TOJDATE('01-JANUARY-2007') FROM DUAL:
D. SELECT TO_CHAR(SYSDATE. 'DD-MON-YYYY') - '01-JAN-2007' FROM DUAL:
E. SELECT TO_DATE(SYSDATE. *DD/MONTH/YYYY') - '01/JANUARY/2007' FROM DUAL:
Answer: B,C
Q159. - (Topic 1)
Evaluate these two SQL statements:
SELECT last_name, salary, hire_date FROM EMPLOYEES ORDER BY salary DESC;
SELECT last_name, salary, hire_date FROM EMPLOYEES ORDER BY 2 DESC;
What is true about them?
A. The two statements produce identical results.
B. The second statement returns a syntax error.
C. There is no need to specify DESC because the results are sorted in descending order by default.
D. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.
Answer: A
Explanation: Explanation: the two statement produce identical results as ORDER BY 2 will take the second column as sorting column.
Incorrect Answer: Bthere is no syntax error Cresult are sorted in ascending order by default DORDER BY 2 will take the second column as sorting column. Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 2-22
Q160. - (Topic 1)
See the Exhibit and examine the structure and data in the INVOICE table: Exhibit:
Which two SQL statements would executes successfully? (Choose two.)
A. SELECT MAX(inv_date),MIN(cust_id) FROM invoice;
B. SELECT MAX(AVG(SYSDATE - inv_date)) FROM invoice;
C. SELECT (AVG(inv_date) FROM invoice;
D. SELECT AVG(inv_date - SYSDATE),AVG(inv_amt) FROM invoice;
Answer: A,D
