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Q131. A Company security System Administrator is reviewing the network system log files. He notes the following:
-Network log files are at 5 MB at 12:00 noon.
-At 14:00 hours, the log files at 3 MB.
What should he assume has happened and what should he do about the situation?
A. He should contact the attacker’s ISP as soon as possible and have the connection disconnected.
B. He should log the event as suspicious activity, continue to investigate, and take further steps according to site security policy.
C. He should log the file size, and archive the information, because the router crashed.
D. He should run a file system check, because the Syslog server has a self correcting file system problem.
E. He should disconnect from the Internet discontinue any further unauthorized use, because an attack has taken place.
Answer: B
Explanation: You should never assume a host has been compromised without verification. Typically, disconnecting a server is an extreme measure and should only be done when it is confirmed there is a compromise or the server contains such sensitive data that the loss of service outweighs the risk. Never assume that any administrator or automatic process is making changes to a system. Always investigate the root cause of the change on the system and follow your organizations security policy.
Q132. What are the default passwords used by SNMP?(Choose two.)
A. Password
B. SA
C. Private
D. Administrator
E. Public
F. Blank
Answer: CE
Explanation: Besides the fact that it passes information in clear text, SNMP also uses well-known passwords. Public and private are the default passwords used by SNMP.
Q133. Exhibit:
Please study the exhibit carefully.
Which Protocol maintains the communication on that way?
A. UDP
B. IP
C. TCP
D. ARP
E. RARP
Answer: C
Explanation: A TCP connection is always initiated with the 3-way handshake, which establishes and negotiates the actual connection over which data will be sent.
Q134. You are manually conducting Idle Scanning using Hping2. During your scanning you notice that almost every query increments the IPID regardless of the port being queried. One or two of the queries cause the IPID to increment by more than one value. Why do you think this occurs?
A. The zombie you are using is not truly idle.
B. A stateful inspection firewall is resetting your queries.
C. Hping2 cannot be used for idle scanning.
D. These ports are actually open on the target system.
Answer: A
Explanation: If the IPID is incremented by more than the normal increment for this type of system it means that the system is interacting with some other system beside yours and has sent packets to an unknown host between the packets destined for you.
Q135. What sequence of packets is sent during the initial TCP three-way handshake?
A. SYN, URG, ACK
B. FIN, FIN-ACK, ACK
C. SYN, ACK, SYN-ACK
D. SYN, SYN-ACK, ACK
Answer: D
Explanation: This is referred to as a "three way handshake." The "SYN" flags are requests by the TCP stack at one end of a socket to synchronize themselves to the sequence numbering for this new sessions. The ACK flags acknowlege earlier packets in this session. Obviously only the initial packet has no ACK flag, since there are no previous packets to acknowlege. Only the second packet (the first response from a server to a client) has both the SYN and the ACK bits set.
Updated ec0-350 free practice questions:
Q136. You want to know whether a packet filter is in front of 192.168.1.10. Pings to 192.168.1.10 don't get answered. A basic nmap scan of 192.168.1.10 seems to hang without returning any information. What should you do next?
A. Use NetScan Tools Pro to conduct the scan
B. Run nmap XMAS scan against 192.168.1.10
C. Run NULL TCP hping2 against 192.168.1.10
D. The firewall is blocking all the scans to 192.168.1.10
Answer: C
Q137. 000 00 00 BA 5E BA 11 00 A0 C9 B0 5E BD 08 00 45 00 ...^......^...E. 010 05 DC 1D E4 40 00 7F 06 C2 6D 0A 00 00 02 0A 00 ....@....m...... 020 01 C9 00 50 07 75 05 D0 00 C0 04 AE 7D F5 50 10 ...P.u......}.P. 030 70 79 8F 27 00 00 48 54 54 50 2F 31 2E 31 20 32 py.'..HTTP/1.1.2 040 30 30 20 4F 4B 0D 0A 56 69 61 3A 20 31 2E 30 20 00.OK..Via:.1.0. 050 53 54 52 49 44 45 52 0D 0A 50 72 6F 78 79 2D 43 STRIDER..Proxy-C 060 6F 6E 6E 65 63 74 69 6F 6E 3A 20 4B 65 65 70 2D onnection:.Keep-070 41 6C 69 76 65 0D 0A 43 6F 6E 74 65 6E 74 2D 4C Alive..Content-L 080 65 6E 67 74 68 3A 20 32 39 36 37 34 0D 0A 43 6F ength:.29674..Co 090 6E 74 65 6E 74 2D 54 79 70 65 3A 20 74 65 78 74 ntent-Type:.text 0A0 2F 68 74 6D 6C 0D 0A 53 65 72 76 65 72 3A 20 4D /html..Server:. 0B0 69 63 72 6F 73 6F 66 74 2D 49 49 53 2F 34 2E 30 ..Microsoft 0C0 0D 0A 44 61 74 65 3A 20 53 75 6E 2C 20 32 35 20 ..Date:.Sun,.25. 0D0 4A 75 6C 20 31 39 39 39 20 32 31 3A 34 35 3A 35 Jul.1999.21:45:5 0E0 31 20 47 4D 54 0D 0A 41 63 63 65 70 74 2D 52 61 1.GMT..Accept-Ra 0F0 6E 67 65 73 3A 20 62 79 74 65 73 0D 0A 4C 61 73 nges:.bytes..Las 100 74 2D 4D 6F 64 69 66 69 65 64 3A 20 4D 6F 6E 2C t-Modified:.Mon,
110 20 31 39 20 4A 75 6C 20 31 39 39 39 20 30 37 3A .19.Jul.1999.07: 120 33 39 3A 32 36 20 47 4D 54 0D 0A 45 54 61 67 3A 39:26.GMT..ETag: 130 20 22 30 38 62 37 38 64 33 62 39 64 31 62 65 31 ."08b78d3b9d1be1 140 3A 61 34 61 22 0D 0A 0D 0A 3C 74 69 74 6C 65 3E :a4a"....<title> 150 53 6E 69 66 66 69 6E 67 20 28 6E 65 74 77 6F 72 Sniffing.(networ 160 6B 20 77 69 72 65 74 61 70 2C 20 73 6E 69 66 66 k.wiretap,.sniff 170 65 72 29 20 46 41 51 3C 2F 74 69 74 6C 65 3E 0D er).FAQ</title>. 180 0A 0D 0A 3C 68 31 3E 53 6E 69 66 66 69 6E 67 20 ...<h1>Sniffing. 190 28 6E 65 74 77 6F 72 6B 20 77 69 72 65 74 61 70 (network.wiretap 1A0 2C 20 73 6E 69 66 66 65 72 29 20 46 41 51 3C 2F ,.sniffer).FAQ</ 1B0 68 31 3E 0D 0A 0D 0A 54 68 69 73 20 64 6F 63 75 h1>....This.docu 1C0 6D 65 6E 74 20 61 6E 73 77 65 72 73 20 71 75 65 ment.answers.que 1D0 73 74 69 6F 6E 73 20 61 62 6F 75 74 20 74 61 70 stions.about.tap 1E0 70 69 6E 67 20 69 6E 74 6F 20 0D 0A 63 6F 6D 70 ping.into...comp 1F0 75 74 65 72 20 6E 65 74 77 6F 72 6B 73 20 61 6E uter.networks.an
This packet was taken from a packet sniffer that monitors a Web server.
This packet was originally 1514 bytes long, but only the first 512 bytes are shown here. This is the standard hexdump representation of a network packet, before being decoded. A hexdump has three columns: the offset of each line, the hexadecimal data, and the ASCII equivalent. This packet contains a 14-byte Ethernet header, a 20-byte IP header, a 20-byte TCP header, an HTTP header ending in two line-feeds (0D 0A 0D 0A) and then the data. By examining the packet identify the name and version of the Web server?
A. Apache 1.2
B. IIS 4.0
C. IIS 5.0
D. Linux WServer 2.3
Answer: B
Explanation: We see that the server is Microsoft, but the exam designer didn’t want to make it easy for you. So what they did is blank out the IIS 4.0. The key is in line “0B0” as you see: 0B0 69 63 72 6F 73 6F 66 74 2D 49 49 53 2F 34 2E 30 ..Microsoft
49 is I, so we get II 53 is S, so we get IIS 2F is a space 34 is 4 2E is . 30 is 0 So we get IIS 4.0
The answer is B
If you don’t remember the ASCII hex to Character, there are enough characters and numbers already converted. For example, line “050” has STRIDER which is 53 54 52 49 44 45 52 and gives you the conversion for the “I:” and “S” characters (which is “49” and “53”).
Q138. This kind of attack will let you assume a users identity at a dynamically generated web page or site:
A. SQL Injection
B. Cross Site Scripting
C. Session Hijacking
D. Zone Transfer
Answer: B
Explanation: Cross-site scripting (XSS) is a type of computer security vulnerability typically found in web applications which allow code injection by malicious web users into the web pages viewed by other users. Examples of such code include HTML code and client-side scripts. An exploited cross-site scripting vulnerability can be used by attackers to bypass access controls such as the same origin policy.
Q139. _______ is one of the programs used to wardial.
A. DialIT
B. Netstumbler
C. TooPac
D. Kismet
E. ToneLoc
Answer: E
Explanation: ToneLoc is one of the programs used to wardial. While this is considered an "old school" technique, it is still effective at finding backdoors and out of band network entry points.
Q140. Bubba has just accessed he preferred ecommerce web site and has spotted an item that he would like to buy. Bubba considers the price a bit too steep. He looks at the source code of the webpage and decides to save the page locally, so that he can modify the page variables. In the context of web application security, what do you think Bubba has changes?
A. A hidden form field value.
B. A hidden price value.
C. An integer variable.
D. A page cannot be changed locally, as it is served by a web server.
Answer: A
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